Question

Calculate the normality of solution of NaOH, if 0.4 g of NaOH is dissolved in 100
ml of the solution.​

Answer 1

Answer:

normally of the solution is 0.1 g-eq/l

Explanation:

weight of naoh =0.4 g

molar mass = 40 g/mol

volume of solution =0.1 L

x factor= no of anions × charge on anion = no of cations × charge on cations

x factor of naoh = 1×1 =1

equivalent mass = molar mass / x factor

equivalent mass of naoh= 40/1 =40

normality = w/(E×V)

N= 0.4/40 × 0.1

N= 0.4/40 = 0.1 g-eq/l (answer)