calculate the number of atoms in 125 g of calcium
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1 mole = 40 g of calcium
1 mole = 6.022 x 10^23
so ,
40g = 6.022 × 10^23
125 g = x ??
(6.022×10^23 × 125)/ 40
(3.011 × 10^22 × 125) /2
will be atoms present in 125 g of calcium
1 mole = 6.022 x 10^23
so ,
40g = 6.022 × 10^23
125 g = x ??
(6.022×10^23 × 125)/ 40
(3.011 × 10^22 × 125) /2
will be atoms present in 125 g of calcium
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