calculate the number of atoms present in each of the sample? . . (atomic mass N=14,O=16). 1. 42g nitrogen. . 2. 80g oxygen
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Answer:
6.022 x 10^22 atoms of N and 1.05 x 10^23 atoms of oxygen
Explanation:
no. of moles = given mass/molar mass
(molar mass is somewhat same as atomic mass)
no. of atoms = no. of moles x Avogadro's number
Avogadro's number = 6.022 x 10^23
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