calculate the number of electrons present in 5 coulomb of charge?
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Q=ne
N=q/e
Here q is the charge,e is the magnitude of charge on 1 electron e=1.6×10^-19
Now
N=5/(1.6×10^-19)
∴n=(5/1.6)×10^19
∴N=3.125×10^19
N=q/e
Here q is the charge,e is the magnitude of charge on 1 electron e=1.6×10^-19
Now
N=5/(1.6×10^-19)
∴n=(5/1.6)×10^19
∴N=3.125×10^19
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