calculate the number of mole of 5.4g of silver
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the number of mole of 5.4g silver..is.......
Al^3+3e=Al
given(atomic mass of Al=27g mol^-1. F=96500 C. mol^-1
solution is.................
-Al^3+3e=Al
-for 1 mol(27.0)g of Al requires=3×96500C
-1g of Al requires=3×96500÷27.0
-5.4 g of Al requires=3×97500×5.4÷27.0
=57900C
I think this answer is useful to you
Al^3+3e=Al
given(atomic mass of Al=27g mol^-1. F=96500 C. mol^-1
solution is.................
-Al^3+3e=Al
-for 1 mol(27.0)g of Al requires=3×96500C
-1g of Al requires=3×96500÷27.0
-5.4 g of Al requires=3×97500×5.4÷27.0
=57900C
I think this answer is useful to you
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