Question

Calculate the number of molecules of oxalic (h2c204.2h2o) in 100 ml of 0.2n oxalic acid solution.

Answer 1

Answer:

Oxalic acid = 6.022×10^21 molecules

◆ Explanation -

# Given -

N = 0.2 N

V = 100 ml = 0.1 L

# Solution -

Normality of a solution is given by formula -

Normality = Gram equivalent of solute / volume of solution

N = E / V

E = N × V

E = 0.2 × 0.1

E = 0.02 g/mol

But gram equivalent is given by formula -

Gram equivalent = no of moles × valence

0.02 = n × 2

n = 0.02 / 2

n = 0.01 mol

No of molecules of oxalic acid present in solution can be given by -

N = n × NA

N = 0.01 × 6.022×10^23

N = 6.022×10^21 molecules