calculate the number of molecules of oxygen gas that occupies a volumeof 224ml at 273k and 3 atm pressure
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Pressure (P) = 3 atm
Temperature (T) = 273 K
Volume (V) = 224 ml = 0.224 L
Gas Constant (R) = 0.0821 atm L K-¹ mol-¹
We know that,
PV = nRT
3 × 0.224 = n × 0.0821 × 273
n = 0.03
number of moles = 0.03
Number of molecules = n×Na
= 0.03 × 6.022 × 10²³
= 1.8 × 10²² molecules
Temperature (T) = 273 K
Volume (V) = 224 ml = 0.224 L
Gas Constant (R) = 0.0821 atm L K-¹ mol-¹
We know that,
PV = nRT
3 × 0.224 = n × 0.0821 × 273
n = 0.03
number of moles = 0.03
Number of molecules = n×Na
= 0.03 × 6.022 × 10²³
= 1.8 × 10²² molecules
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