Question

calculate the number of molecules of phosphorus present in 248 gram of solid Sulphur​

Answer 1

248 gm of solid phosphorus = 248/31 = 8 moles.

1 mole of phosphorus = 6.022x1023 molecules.

8 mole of phosphorus = 8 x 6.022x1023

= 48.176 x 1023 molecules.

Answer 2

Explanation:

No. of molecule = given mass / molar mass =31×4u = 124u

No. of moles= 248/124 × 6.022×10^23

=2×6.022×10^23

=12.022×10^23 ans.