calculate the number of moles in 490g of sulphuric acid (GMM of H2SO4=98g). calculate the total number of atoms present in this much amount of sulphuric acid
Answers
The molecular mass of H2SO4 is 98 and this contribution of H- atom is 2. Upon dissociation of 1 molecule of H_2
SO_4 , 2 atoms of hydrogen ion is released.
We know that,
No. of moles, n = Given mass/ Atomic mass
∴ No. of moles of H_2
SO_4
=4.9/98=0.05
⇒ No. of H-atom = 2 x n x Avogadro no.
= 2 x 0.05 x 6.023 x 10^23
= 6.022 x 10°22
Given: 490 g of sulphuric acid is given. Molar mass of sulphuric acid= 98 g.
To find: 1-Number of moles in 490 of sulphuric acid
2- total number of atoms present in this much amount of sulphuric acid
Explanation: Given mass= 490 g
Molar mass = 98 g
Moles= given mass/molar mass
= 490/98
= 5 moles
Number of atoms in 1 mole of this compound= 2 hydrogen atoms+ 1 sulphur atom+ 4 oxygen atom= 7
Number of atoms in 5 such moles= 5*7= 35
Therefore, total number of atoms= 35* Avogadro number
=> Total atoms= 35*6.02* 10^23
= 210.7 * 10^23 atoms
Therefore, total number of moles is 5 and total number of atoms is 210.7* 10^23.