Calculate the number of moles of ethylene required to produce 44g CO2 gas on its complete combustion
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The answer is 0.5 mol.
Formula for the complete combustion of methane with oxygen: CH4 + 2O2 -> CO2 + 2H2O
Molecular mass of CO2 = 12 + 2(16) = 44 g
Combining 1 and 2, 1 mol CH4 = 44 g (1 mol) CO2
By proportion, 0.5 mol CH4 in complete combustion = 22 g CO2.
Formula for the complete combustion of methane with oxygen: CH4 + 2O2 -> CO2 + 2H2O
Molecular mass of CO2 = 12 + 2(16) = 44 g
Combining 1 and 2, 1 mol CH4 = 44 g (1 mol) CO2
By proportion, 0.5 mol CH4 in complete combustion = 22 g CO2.
mudageritu:
But there they've asked about ethylene not methane
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