Calculate the number of moles of H,SO, present in 50 ml of 0.2 M H SOL
Answers
Answer:
Molarity (M) : The number of moles of a solute dissolved in 1 L (1000 ml) of the solution is known as the molarity of the solution.
Molarity of a solution
(M)=
molar mass of solute
mass of solute
×
volume of solution in mL
1000
∴0.2=
40
w
×
500
1000
so w=4gm.
Amount of sodium hydroxide present in 500ml of 0.2M solutions is 4 gm.
Halogens act as strong oxidising agents because they have high tendency to accept electron, i.e., they have high electron affinity values. The reduction potentials are high ( positive ) and decreased from FF to I .
The Group 2 alkaline earth metals include Beryllium, Magnesium, Calcium, Barium, Strontium and Radium and are soft, silver metals that are less metallic in character than the Group 1 Alkali Metals. Although many characteristics are common throughout the group, the heavier metals such as Ca, Sr, Ba, and Ra are almost as reactive as the Group 1 Alkali Metals. All the elements in Group 2 have two electrons in their valence shells, giving them an oxidation state of +2.
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