Question

Calculate the number of oxygen atoms in 0.10 mol of na2co3.10h2o

Answer 1

M.W of Na2CO3.10H2O = (2 * 23) + 12 + (3 * 16) + (10 * 18) = 286g

Of this 48 + 160 = 208g is O (per Mole)

For 0.10 mol amount of Oxygen = 20.8 g

Answer 2

Please refer the attachment please.....!!