calculate the percentage composition of C12 c14 is average atomic mass is 13.6 u
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Let c12=X12
c14=Y14
X12 or c12
12X+14(100-X)/100=13.6
12X+1400-14X=1360
-2X=1360-1400
-2X=-40
X=40/2=20%
(anytime be 100% so 20% begot to find another one 100%-20%=80%)
Y14 or c14
14Y+12(100-Y)100=13.6
14Y+1200-12Y=1360
2Y=1360-1200
2Y=160
Y=160/2=80%
So,X12 or c12=20% and Y14 or c14=80%
20%+80%=100%
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