Question

calculate the percentage of nitrogen in NH3.(Atomic Mass of N=14,H=1amu)

Answer 1

use the molar mass and assume 100 g multiple by 100.

N = 14.01 g N /17.034 g NH3 x100 = 82%
H = 3.024 g H /17.034 g x100 = 18%

Answer 2

Answer: 82.35%

Explanation:

${\text {percentage of nitrogen}}=\frac{\text {mass of nitrogen}}{\text { mass of ammonia}}\times 100\%$

Mass of nitrogen = 14 amu

Mass of ammonia $(NH_3)=14 +4\times 1=17 amu$

${\text {percentage of nitrogen}}=\frac{14}{17}\times 100\%=82.35\%$