Calculate the ph of 0.001m naoh by
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Answered by
1
the answer for your questioin is
[OH–] = 0.001 M.
pOH =–log(0.001) = 3
and pH = 14 – pOH = 14 – 3 = 11
[OH–] = 0.001 M.
pOH =–log(0.001) = 3
and pH = 14 – pOH = 14 – 3 = 11
Answered by
0
Since [H]×[OH]=10^-14
[H]×[10^-3]=10^-14
[H]=10^-11
From here you can calculate pH which will be 11
[H]×[10^-3]=10^-14
[H]=10^-11
From here you can calculate pH which will be 11
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