Question

Calculate the pH of a solution prepared by mixing equal values of the solutions of pH=5 and pH=4

Answer 1

Answer:

3.85

Explanation:

[H+] for pH 5 is 10^(-5) and for pH 4 it is 10^(-4)

so, M1V1 +M2V2 =M(V1+V2)

Volume is equal (given)

Let it be V

{10^(-5)V+10^(-4)V}/2V = M

thus M= 0.55 * 10^(-4)

thus pH is -log 0.55*10^-4

pH is almost equal to 3.85