Question

calculate the phase difference between two points 2into 10 to the power -5cm apart on a wave of wave length 4000A

Answer 1

Hii friend,

● Answer -
Φ = 3.142 rad

● Explanation -
# Given -
d = 2×10^-5 cm
λ = 4×10^-5 cm

# Solution -
Phase difference is calculated by -
Φ = 2πd / λ
Φ = 2 × 3.142 × 2×10^-5 / 4×10^-5
Φ = 3.142 rad

Hence, the phase difference between two points is 3.142 rad.

Hope this helped you...

Answer 2

Phase difference ∅= (2πd)/λ

     Given d= 2×10⁻⁷m

    λ= 4000 A

So phase diff. ∅= (2×3.14×2×10⁻⁷)/4000

                         = 3.14 rad= π rad