Question

Calculate the potential energy in case of dipole having magnitude of each charge as 3 × 10 raise to the power minus 6 C .The charge are separated at a distance of 2000 A​

Answer 1

Answer:

An electric dipole of length 10 cm having charges ±6×10

−3

C placed at 30

o

w.r.t. a uniform electric field experiences a torque of magnitude 6

3

Nm. Calculate (1) magnitude of electric field (2) potential energy of dipole.

ANSWER

Dipole moment (p)=q.d=(6×10

−3

).0.1=6×10

−4

Cm

Torque(τ)=p×E=pEsinθ=6

3

Nm

⇒(6×10

−4

)×E×sin30

0

=6

3

⇒E=2

3

×10

4

N/C

Now, Potential Energy =

p

.

E

=pEcosθ=(6×10

−4

)×(2

3

×10

4

)×cos60

0

=18J

Explanation:

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