Calculate the power of an electric motor that can lift 800 kg of water to store in a tank at a height of 1500 cm in 20 s. (g = 10 m / s^2)
Answers
Answered by
4
Hey!
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Mass of water= 800 kg
Height of tank= 1500 cm = 150 m
Time= 20s
Gravity due to acceleration= 10 m/s^2
Power=?
P= mgh/t
P= 800×10×150/20
P= 60,000 W
P= 60 kW
_________________________
Hope it helps...!!!
_________________________
Mass of water= 800 kg
Height of tank= 1500 cm = 150 m
Time= 20s
Gravity due to acceleration= 10 m/s^2
Power=?
P= mgh/t
P= 800×10×150/20
P= 60,000 W
P= 60 kW
_________________________
Hope it helps...!!!
Answered by
2
Power= mgh/t
Mass of load= 800kg
Height of tank = 1500 cm = 150 m
Time = 20s
g= 10 m/s^2
Power = mgh/t
P= 800×10×150/20
P= 60kW
Mass of load= 800kg
Height of tank = 1500 cm = 150 m
Time = 20s
g= 10 m/s^2
Power = mgh/t
P= 800×10×150/20
P= 60kW
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