Question

Calculate the power of an engine in terms of HP which needed to lift 1000 kg of coal in 30 minute
from coal mine 100 m deep. Given g=10 ms.
​

Answer 1

Answer:

work W=P.t=m.g.H

P=m.g.H/t

=1000×10×100/30×60

=555.556 watt.

=555.556÷746 HP

=.7447 HP

Explanation:

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Answer 2

The power of an engine is 0.73 HP.

Explanation:

Given that,

Mass of the coal, m = 1000 kg

It is lifted from coal mine 100 m deep, d = 100 m

Time, t = 30 min = 1800 s

We need to find the power of an engine. Power of an object is given by work done per unit of time.

$P=\dfrac{W}{t}$

W = mgh

$P=\dfrac{mgd}{t}$

$P=\dfrac{1000\times 9.8\times 100}{1800}$

P = 544.45  Watts

Since, 1 horse power = 746 watts

Power, P = 0.73 HP

So, the power of an engine is 0.73 HP. Hence, this is the required solution.

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