Math, asked by Anonymous, 3 months ago

Calculate the pressure exerted by a brick, which applies force of 2.5 N, when (a) it is placed upright on the soil (b) when it is placed on its widest base. The dimensions of the brick are 25 cm × 10 cm × 5cm​

Answers

Answered by devindersaroha43
6

Answer:

Step-by-step explanation:

500 Pa and that of (b) is 100 Pa.

Explanation:

Thrust(Compressive force) = 2.5 N .

a).

Area of cross-section = {(5cm * 10 cm) / (100*100)} m².

= 1 / 200 m²

Therefore, Pressure =

\frac{force \: exerted}{area \: of \: cross \: section}

areaofcrosssection

forceexerted

= 2.5N / (1/200) m².

= 500 Nm.

= 500 Pa.

b).

Area of cross-section = {(25cm * 10 cm) / (100*100)} m².

= 1 / 40 m²

Therefore, Pressure =

\frac{force \: exerted}{area \: of \: cross \: section}

areaofcrosssection

forceexerted

= 2.5N / (1/40) m².

= 100 Nm.

= 100 Pa.

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