Calculate the pressure exerted by a brick, which applies force of 2.5 N, when (a) it is placed upright on the soil (b) when it is placed on its widest base. The dimensions of the brick are 25 cm × 10 cm × 5cm
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Answer:
Step-by-step explanation:
500 Pa and that of (b) is 100 Pa.
Explanation:
Thrust(Compressive force) = 2.5 N .
a).
Area of cross-section = {(5cm * 10 cm) / (100*100)} m².
= 1 / 200 m²
Therefore, Pressure =
\frac{force \: exerted}{area \: of \: cross \: section}
areaofcrosssection
forceexerted
= 2.5N / (1/200) m².
= 500 Nm.
= 500 Pa.
b).
Area of cross-section = {(25cm * 10 cm) / (100*100)} m².
= 1 / 40 m²
Therefore, Pressure =
\frac{force \: exerted}{area \: of \: cross \: section}
areaofcrosssection
forceexerted
= 2.5N / (1/40) m².
= 100 Nm.
= 100 Pa.
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