Question

Calculate the radius and energy associated with
second orbit of Li+ atom.

Answer 1

Answer:

The radius and energy associated with the second orbit of Li⁺ atom is 0.7053A° and -30.6eV respectively.

Explanation:

The radius of nth orbit is given by

              $r_n = a_0\frac{n^{2} }{Z}\; A^{0}$

                                           where,

                                                   z = atomic number

                                                 a₀ = 0.529 A°= Bohr's radius

the energy associated with the nth orbit

              $E_n = -13.6\frac{Z^{2} }{n^{2} } \;eV$  

Given

n = 2 and Z = 3

the radius of the second orbit of Li⁺ atom is

$r_2 = 0.529\times\frac{2^{2} }{3}=0.7053A^{0}$

the energy associated with the second orbit of Li⁺ atom is

$E_2 = -13.6\times\frac{3^{2} }{2^{2} }=-30.6eV$

the required answer is

$r_2 }=0.7053A^{0}$ and $E_2 =-30.6eV$