Physics, asked by akshaychoudhary5049, 1 year ago

Calculate the resistance of an aluminium cable of length 10 km and diameter 2.0 mm if the resistivity of aluminium is 2.7 into 10 raise to the power minus 8 ohm metre

Answers

Answered by QGP
40
Here we have the following data:

Length = l = 10\, \, km = 10^4 \, \, m \\ \\ Diameter = d = 2.0 \, \, mm \\ \\ Radius = r = 1.0 \, \, mm = 10^{-3} \, \, m \\ \\ Resistivity = \rho = 2.7 \times 10^{-8} \, \, \Omega m


To find the Resistance, we use the following relation:

R = \rho \frac{l}{A} \\ \\ \\ \implies R = \rho \frac{l}{\pi r^2} \\ \\ \\ \implies R = (2.7 \times 10^{-8}) \left( \frac{10^4}{\pi \times (10^{-3})^2} \right) \\ \\ \\ \implies R = (2.7 \times 10^{-8}) \times \frac{10^4}{\pi \times 10^{-6}} \\ \\ \\ \implies R = \frac{270}{\pi} \\ \\ \\ \implies \boxed{R \approx 85.94 \, \, \Omega}


Thus, the  Resistance is approximately 85.94 Ohms. 

Hope it helps
Purva
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Answered by Rukshanaa14
27

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