Question

calculate the resistance of an aluminium wire of length 60 cm and cross section area 1 mm square. The specific resistance of aluminium is 2.6× 10 ka power minus 8 ohm - m

Answer 1

the resistance is given as

R = ρL / A

here

ρ = 2.6x10⁻⁸ ohm-m

L = 60 cm = 0.6m

A = 1 mm² = 10⁻⁶ m

²

so, we have

R = (2.6x10⁻⁸ X 0.6) /10⁻⁶

thus,

R = 1.56 x 10⁻² ohms

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Answer 2

The resistance of the aluminium wire of length 60 cm, cross section area 1mm^2 and specific resistance or p is equal to 2.6 ×10^-8.

Now to find the resistance of this aluminum wire we need to calculate it through the basic formula of resistance.

Resistance = R =( p × l)/A

where l = length of wire = 60 cm= 0.6 m

A= Cross sectional area = 1mm^2 = 1×10^-6 m^2

Now calculating the value of resistance

R = p × l /A = 2.6 × 10^-8 × 0.6 /10^-6 = 2.6×0.6 ×10^-2 = 1.56 ×10^-2 ohm.
Hence the value of resistance present in the system is 1.56 ×10^-2 ohm.