Question

calculate the simple interest on :-
₹5000 in 1 year at 6% per annum

also find its amount?????
itzzzzz urgent....​

Answer 1

300......

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Answer 2

$\sf{{Given:-}}$

$\sf{{Principal \ = \ Rs.5000}}$

$\sf{{Time \ = \ 1 \ year}}$

$\sf{{Rate \ = \ 6 \% p.a.}}$

$\sf{{To \ Find:-}}$

• $\sf{{Simple \ Interest}}$

• $\sf{{Amount}}$

$\sf{{Solution:-}}$

$\sf{{We \ will \ apply \ the \ formula:-}}$

$\sf{{Simple \ Interest \ =}}$$\sf\dfrac{P\times R\times T}{100}$

$\sf\dfrac{= 5000\times 6\times 1}{100}$

$\sf{{=50\times 6}}$

$\sf{{=Rs.300}}$

$\sf{{As \ we \ know \ S.I. \ is \ 300}}$

$\sf{{So,}}$

$\sf{{Amount = P + I}}$

$\sf{{= 5000 + 300}}$

$\sf{{= Rs.5300}}$

$\sf{{Required \ Answer:-}}$

• $\sf{{Simple \ Interest}}$$\sf{{=Rs.300}}$

• $\sf{{Amount}}$$\sf{{= Rs.5300}}$

★ $\sf{{ Note \ :- \ P \ denotes \ Principal, \ R \ denotes \ Rate, \ T \ denotes \ Time \ and \ I \ denotes \ Interest.}}$

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$\sf{{Let \ us \ know \ more \ Formulas:-}}$

• $\sf{{C.I. \ = \ A - P}}$

• $\sf{{R \ =}}$$\sf\dfrac{100\times I}{P\times T} \%$

• $\sf{{A=P(1+}}$$\sf\dfrac{r}{100})^{n}$

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