Question

calculate the size of unknown angle..

pls help ill mark u as brainlinest!
I'll report the answer who will write nonsence like I don't know and all....
pls help​​

Answer 1

Step-by-step explanation:

AS U KNOW THE TOTAL MEASURE OF ALL ANGLES IN A TRIANGLE IS 180 DEGREES

SO THE UNKNOWN ANGLE WILL BE

1. 90+50= 140

SO 180-140= 40

2.IN BOTH THE SIDES THE ANGLES SHOULD BE SAME

SO 75+ 75 DEGRESS= 150

SO 180- 150= 30 ( I DONT KNOW EXACTLY)

3. 65+55= 120

SO 180- 120= 60

AS THERE IS A DIVIDER

SO MEASURE OF e) 30 DEGRESS

f) also 30 degress

4. 90+ 47= 137

180- 137= 43 degress

5. both sides equal and 90 degree is given

180-90= 90

and equally is 45 degrees

6. see

theere is 90 degree

and we have 63 degree

so left is 180-(90+63)= 180- 153= 27

so g is 27 degrees

and h is same as g

so h= 27 degrees

and that 63 and some angle is making a linear pair

so other angle that should be joined with 63 degree is 117

so other angle is 117

and now we have all

so i) 180-(27+ 117)= 180-144= 36

so u got all angles

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Note:- Plz check me answers horizontally not vertically it is my mistake

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Answer 2

Answer:

a) 40

b) 43

c)105

d) think its 90, not too sure

e)25

f)25

g)27

h)not sure about h

i) 63

Step-by-step explanation:

a) the inside of a triangle equals 180.  add 90+50=140, then subtract it 180-140= 40 therefore a =40

b)the block in the corner equals 90. add 90+47=137, 180-137= 43 therefore b=43

c) 180-75=c, 180-75=105, therefore 105=c

d)

e)65+90=e. 65+90=155, 180-155=25

f)55+90=f, 180-155=25, therefore f=25

g) 63+90=g, 180-153=27, therefore g=27

i) i=63 because of alternate angles