Question

Calculate the standard emf of cu2+/cu electrode if the cell potential of the cell :Mg(s)/Mg2+(0.001)//cu2+(0.0001m)/cu(s) is 2.6805V
Given:E°(mg2+/mg)=-2.37V​

Answer 1

Answer:

E°(cu+2|cu) = 5.0801V

Explanation:

reduction at LHE: Mg+2 + 2e->Mg E°(mg2+|mg)=-2.37V--(1)

reduction at RHE: Cu+2 +2e-->Cu E°(cu+2| cu)=-2.37V--(2)

net cell reaction

(2)-(1)

from this onwards there is an attached pic .

Hope this would help.

Answer 2

Answer:

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Explanation:

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