Question

What is the formula you will use to calculate how many milliliters of 5.5 M NaOH are required to prepare 400 mL of 1.5M NaOH?​

Answer 1

Given

final

molarity of NaOH(Mf) = 5.5M

volume (Vf)= 400ml= 400/100= 0.4L

since 1 L = 1000ml

initial

Molarity of NaOH(Mi) = 1.5M

vi=?

Formula

we know that According to law of equilibrium of mixture

Mi*Vi= Mf*Vf

Vi = 1.5*0.4/5.5 = 0.1liter