Chemistry, asked by Rishu5132, 1 year ago

calculate the temperature to which a gas must be heated,so that the volume triples without any change in pressure. the gas is originally at 57 degree celcius and having a volume 150cc.

mohanmanjhi5: C2H2 + 5/2O2 ----------------> 2CO2 + H2O

Burning of 1 mole of C2H2 requires 2.5 mole O2

That means 2.5 x 22.4 L = 56000 cm3 O2

Let total air required is = M

20% of air = 56000 cm3 O2

20 M/100 = 56000 cm3 O2

M = 56000 x 100/20 = 280000 cm3

Answers

Answered by megharana957

Answer:

= 717⁰C

Explanation:

V¹= 150cc

T¹= (57+273)= 330 K

V²= 3×150= 450cc

T²=?

at constant pressure V¹/T¹= V²/T²

T²= V²T¹/V¹

T²= 450×330/150= 990K

= 990-273= 717⁰C.

Previous Question

Next Question