Question

calculate the time in which a tuning fork of frequency 256 Hz complete 32 oscillation

Answer 1

Time required to complete 256vibrations=1second
Time taken to complete 1 vibration=1/256sec
Time taken to complete 32oscillayion=
1/256×32
=1/8seconds.

Answer 2

The time taken by the tuning fork of frequency 256 Hz to complete 32 oscillation is 0.125 seconds.

Explanation:

It is given that,

Frequency of the tuning fork, f = 256 Hz

Number of oscillation, n = 32

We know that the frequency of the tuning fork or any object is defined as the total number of oscillations per unit time. It is given by :

$f=\dfrac{n}{t}$

t is the time taken to oscillate

$t=\dfrac{n}{f}$

$t=\dfrac{32}{256}$

t = 0.125 seconds

So, the time taken by the tuning fork of frequency 256 Hz to complete 32 oscillation is 0.125 seconds

Learn more,

Frequency

https://brainly.in/question/3410550