Question

find the value of log 343 to the base 3

Answer 1

Answer:

$\log_33433\log _3\left(7\right)=5.31$

Step-by-step explanation:

Given: $\log_3343$

We have to find the value of given expression $\log_3343$

Consider the given expression $\log_3343$

$\mathrm{Rewrite\:}343\mathrm{\:in\:power-base\:form:}\quad 343=7^3$

$=\log _3\left(7^3\right)$

$\mathrm{Apply\:log\:rule}:\quad \log _a\left(x^b\right)=b\cdot \log _a\left(x\right)$

We get ,

$\log _3\left(7^3\right)=3\log _3\left(7\right)$

$=3\log _3\left(7\right)$

Thus, $\log_33433\log _3\left(7\right)=5.31$

Answer 2

Given:

$\bold{\log_3 (343 )}$

To find:

Value=?

Solution:

$\log(343)= 2.53529412004\\\\ \log(3)=0.47712125472$

Solve given equation:

$\Rightarrow \log_3 (343 )= \log(343) \div \log(3)$

                   $=\ 2.53529412004 \div 0.47712125472$

                   $=5.31373124748$

The final value is: "5.31373124748".