Question

calculate the time taken by a body starting from rest moving with a velocity of 1000 m/s with acceleration of 50 m/s^2.​

Answer 1

Answer:

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Explanation:

v = 1000 m/s

u = 0

a = 50 m/s²

t = ?

v = u + at

⇒ 1000 = 0 + 50 × t

⇒ 1000 = 50t

⇒t = {\it{\dfrac{1000}{50}}}

50

1000

⇒ t = 20 s

Answer 2

Answer:

Given :

Initial velocity ,u = 0m/s

Final Velocity ,v = 1000m/s

Acceleration ,a = 50 m/s²

To Find :-

Time taken by a body ,t

Solution:-

According to the Question

It is given that body starts from rest and moving with velocity of 1000m/s.

we have to calculate the time taken by body .

We use here kinematics equation

v = u + at

where,

v is the final velocity

a is the acceleration

u is the initial velocity

t is the time taken

by putting the value we get

↠ 1000 = 0 + 50×t

↠ 1000 = 50t

↠ 1000/50 = t

↠ t = 1000/50

↠ t = 20s

Hence, the time taken by body will be 20 seconds .

Explanation:

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