Question

Calculate the total number of neutrons present in 4 gm of MgO

Answer 1

no of moles=4/24+16=4/40=1/10

No of atoms=1/10* 6*10^23=6 * 10^22

1 atom of Mg has 12 n

1 atom of O has 8 n

total neutron= 20

overall neutron=6* 10^22*20= 120 * 10^22

Answer : 1.2 * 10^24

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