Calculate the total resistance and current in the circuit if R2, R3, R4 are 2Ω and R1 is 4Ω. Potential difference across the battery is 12V PLS ANSWER IT CORRECTLY I'LL SURELY MARK YOU BRAINLIEST
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Answer:
if all are connected in series, then
equivalent resistance R = 10ohm
then current I = V/R= 1.2A
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Given,
R2 = R3 = R4 = 2Ω
R1 = 4Ω
V = 12V
R(ef) = ?
I guess the question is R2,R3 and R4 connected in series and R1 is connected in parallel..?
R(series) = R2 + R3 + R4
= 2Ω + 2Ω+ 2Ω
= 6Ω
Now, R(series) and R1 are in parallel.
⇒ 1 1 1
------ = ------ + ------
R(p) 6 4
1 4 + 6
------ = -----------
R(p) 24
∴R(p) = 24 / 10
Hence, the total resistance in the circuit is 24/10Ω
Is the potential difference given for finding the current?
V = IR
⇒ I = V/R
= 12 × 10
------------
24
∴ I = 5A
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