Question

Calculate the vertical distance travelled by an object dropped from rest if it travels for 60 seconds without air resistance.

Answer 1

Answer:

Initial velocity of the body u=0

Distance covered in t

th

second, S

t

=u+

2

1

g(2t−1)

∴ S

t

=0+

2

1

g(2t−1)=

2

1

g(2t−1)

Distance travelled in first second i.e. t=1, S

1

=

2

1

g(2×1−1)=

2

1

g

Distance travelled in 2nd second i.e. t=2, S

2

=

2

1

g(2×2−1)=

2

3

g

Distance travelled in third second i.e. t=3, S

3

=

2

1

g(2×3−1)=

2

5

g

⟹ S

1

:S

2

:S

3

=1:3:5