Question

Calculate the volume at n.t.p occupied by : (a) 14 g of nitrogen

Answer 1

given wt = 14 g
molecular wt = 28 g/mol
no of mole = given wt/molecular wt
= 14/28 = 0.5

volume = no of mole × 22.4 L
= 0.5 × 22.4 L
= 11.2 L

Answer 2

Answer:

The volume at NTP occupied by 14 g of nitrogen is 11.2 liters.

Step-by-step explanation:

Given : 14 g of nitrogen.

To find : Calculate the volume at n.t.p occupied by nitrogen ?

Solution :

We know that,

At NTP a mole of any gas weighs 22.4 litres.

Now, The number of moles in 14 g of nitrogen is

Molecular weight W= 28 g/mol

Given weight w=14 g

$n=\frac{w}{W}$

$n=\frac{14}{28}$

$n=\frac{1}{2}$

$n=0.5$

Volume of 1 mole is 22.4 liters.

So, volume of 0.5 mole is $22.4\times 0.5$

Volume of 0.5 mole is 11.2 liters.