Question

Calculate the volume at S.T.P of 3.5✖️10-3kg of nitrogen

Answer 1

Answer:

I read 3.5 into 10 raise to minus 3 kg to be 3.5 x 10^-3 kg. See how easy that is?

Molar mass N2 = 28g/mol

3.5*10^-3kg = (3.5*10^-3) *1000 = 3.5g

Mol N2 in 3.5g = 3.5g / 28g/mol = 0.125 mol N2

1 mol N2 at STP has volume = 22.4L

0.125 mol N2 at STP has volume = 0.125mol x 22.4L/mol = 2.8L

Volume = 28 litres.

Answer 2

Answer:

answer give by above person is wrong is wrong the right answer will be 2.8L at STP the step answer is given in the image hope it will help you