Question

calculate the volume occupied by 0.46g of nitrogen dioxide at S.T.P.[N=14,O=16].

Answer 1

Hlo friend.. Cutiepie Here..

Here is ur answer :

Volume occupied by 1 mole at STP = 22.4 L

Molecular mass of Nitrogen Dioxide

NO
²

Atomic mass of

Nitrogen = 14

Oxygen = 16

= 14 + ( 16 × 2)

= 14 + 32

= 46 u

No. Of moles

$= \frac{given \: \: mass}{molecular \: \: mass}$


Given mass = 0.46

$= \frac{0.46}{46}$


$= 0.01$


Volume occupied by 0.01 mole =

22.4 × 0.01

= 0.224 l

ANS Volume occupied by 0.46g of nitrogen
dioxide at STP is 0.224 l


HOPE IT HELPS YOU..

Answer 2

Answer:the answer is 224cc

refer the attachment