Question

Calculate the volume occupied by 28 gram and N2 gas at STP

Answer 1

no of moles = given weight /molecular wt
here ,
given wt = 28 g
molecular wt of N2 gas = 28g /mol

no of moles = 28/28 = 1

volume of N2 gas at NTP = no of moles × 22.4 L
= 1 × 22.4 L
= 22.4 L

Answer 2

Moles of $N_{2}$ = $\frac{28}{14*2}$ = 1
Volume occupied at STP = moles * 22.4 = 1 * 22.4 = 22.4 L