Question

Calculate the volume of ammonia formed at STP by reacting completely 0.05mol of ammonia chloride with calcium hydroxide

Answer 1

Answer:

0.05/22.5=0.022

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Answer 2

The volume of ammonia formed at STP by reacting completely 0.05mol of ammonia chloride with calcium hydroxide is 1.12L

The reaction when NH4Cl (ammonium chloride) reacts with Ca(OH)2 (calcium hydroxide):

2 NH4Cl + Ca(OH)2 → 2 NH3 + CaCl2 + 2H2O

∴ From the reaction, we can easily understand that 2 moles of ammonium chloride (NH4Cl) is required to produce 2 moles of ammonia (NH3).

So, 1 mole NH4Cl is reqd. to produce 1 mole NH3.

So, 0.05 moles of NH4Cl is reqd. to produce 0.05 moles NH3.

As volume occupied by 1 mole of any gas at STP is 22.4L

∴ Volume occupied by 0.05 moles of NH3 gas at STP is (22.4 × 0.05)L = 1.12L

So, volume of ammonia formed at STP by reacting completely 0.05mol of ammonia chloride with calcium hydroxide is 1.12L