Question

Calculate the volume of o2 at stp required for the complete combustion of 125 octane

Answer 1

Answer:

Write the balance equation-

2 C8H18 + 17 O2 --> 16 CO2 + 18H2O

125 g octane / 114.2 g/mol = 1.094 mol

2 moles of octane require 17 moles of oxygen so 1.094 moles of octane require 9.30 moles of oxygen (17 x 1.094/2 = 9.30)

9.30 mol O2 x 22.4 L/mol = 208 L O2