Chemistry, asked by Anonymous, 6 months ago

Calculate the wave number and energy of the
spectral line emitted by an excited hydrogen atom
corresponding to n, = 3 and n2 = 5.
dudes and dudets the answer is

wave number = 7.8*10^3cm^-1
and
energy = 1.55*10^-19
I want solutions not the answer.
Please send it

#challange_from_me​

Answers

Answered by sambabitra
0

Answer:

Pb(NO3)2 Δ-> PbO + O2 + NO2 . The number of NO2 molecules in balanced equation are​

Explanation:

Pb(NO3)2 Δ-> PbO + O2 + NO2 . The number of NO2 molecules in balanced equation are​....

Answered by Anonymous
0

Answer:

lakin fir bhi is type ke question post nhi kar na chaheye

vese bhi fokat point waste hoge or kuch nhi hoga .

Similar questions