calculate the wavelength associated with 1 mev electron
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F=frequency (in per second)
W= wavelength(in metre)
E=energy(in joule)
C= velocity of light(3×10^8m/s)
h=planks constant(6.65×10^-34)
E=hF
F=C/W
E=hC/W
we have to find W
E=1Mev= 1.6×10^-19 ×10^6
E=1.6×10^-13
(1ev= 1.6×10-19 Joule
1M=10^6 Joule)
Now,
hC=6.65×10^-34×3×10^8
hC= 2×10^-25
W=hC/E
W=2×10^-25÷1.6×10^-13
W=20 ×10^-12÷16
W=1.25×10^-12metre
I hope this is the answer if I am wrong then please let me know
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