calculate the weight of co having the same number of 02 atoms present in 22g of co2
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Wt of o2 in co2= wt of o2 in CO
44grams of Co2 ----> 2 atoms of O
= 2* 6.023*10^23 atoms of O
Therefore,
22grms of Co2 has---> 6.023*10^23 atoms of O (1mole of oxygen)
Thus.. weight of CO = 12+16= 28grns
44grams of Co2 ----> 2 atoms of O
= 2* 6.023*10^23 atoms of O
Therefore,
22grms of Co2 has---> 6.023*10^23 atoms of O (1mole of oxygen)
Thus.. weight of CO = 12+16= 28grns
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