calculate the weight of h2so4 in 250cc when the solution contains 98% h2so4 by weight??
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Hey.....this may help u......
98% aqueous H2SO4 solution by mass contains 98g of H2SO4 and 2g of water.
Thus in 98% aqueous H2SO4 solution, we have 1 mol of H2SO4, 0.11 mol of water and 1.11 mol of solution (total no. of moles of both the solutes). Calculation follows.
no. of moles of H2SO4 = (98g)/(98g/mol) = 1 mol,
no. of moles of H2O = (2g/18g/mol) = 0.11 mol.
Thus mole fraction of H2SO4 is 0.9.
decentgirl010:
Dear I'm not asking about mole fraction!
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98% solution means 98g H2SO4 in 100g solution.
Therefore it contains 1 mole of H2SO4 and (2/18) moles of water.
Mole fraction of H2SO4 = 1/(1+ 2/18) = 18/20 = 0.9
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