Question

calculate the weight of NaCl present in 250 g of 0.01 m solution

Answer 1

According to formula

The number of moles of a solute (NaCl in this case) is equal to the concentration multiplied by the volume (in L).

ie. n = c x v

So the number of moles of NaCl is 4.31x 0.01 = 0.0413 moles

Now, the mass of a solute equals the number of moles multiplied by its molar mass.

ie. mass = n x MM

So the mass of NaCl = 0.0431 x (22.9898 + 35.453) = 2.51 g

I hope this will help you