Chemistry, asked by dachepallianji, 10 months ago

calculate the weight of NaoH present in 200 ml of 0.5M solution

Answers

Answered by amir2313

2

Explanation:

the amount of NaOH present in 200 mL of 0.5 N solution. W=(0.5 equiv L-1)×(40 g equiv-1)×(0.2 L)=4g.

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