Question

calculate the work done for the reversible isothermal expansion of 160 gram of argon at 30 degree Celsius from a volume of 8 litre to volume of 20 litre assuming the argon is monoatomic ideal gas​

Answer 1

Answer: - 9.233KJ

Explanation:

No.of mol of Ar = 160g/40g/mol =4mol

T= 303k , V1 =8L , V2 = 20L, R=8.314J/K/mol

Work done= -2.303×nRTlogV2/V1

= - 2.303× 4× 8.314×303 log20/8

= -9.233KJ