Calculate the work done when 3 mole of ideal gas at 27^c expand isothermally and reversibly from 10 atm to 1 atm
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Answered by
34
Answer:
For an isothermal process
W=2.303nRTlogp1/p2p where p1 =10 atm
P2 =1 atm
W=2.303×3×8.314×300×log10/1
W=17232.42 J
W=17.232.42 KJ
Explanation:
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Answered by
9
Answer:
For an isothermal process
W=2.303nRTlogp1/p2p where p1 =10 atm
P2 =1 atm
W=2.303×3×8.314×300×log10/1
W=17232.42 J
W=17.232.42 KJ
Explanation:
Hope this may help you...
✳️✨ Niharika ✨✳️
✨ Follow me ✨
☺️ keep smiling ☺️
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