Question

calculate the work involved when a system absorbs 200j of heat while the internal energy of the system decreases by 100j
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Answer 1

hey there is answer !!
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Change in energy given by:

dQ = du + dw

 

dQ = 500 J

 

dw = - 100 J

 

du = dQ - dw

 

     = 500 - ( -100 )

 

     = 600 J

Answer 2

Answer:

The answer is 300 joule

Explanation:

We can observe how these parameters interact to impact the amount of growth that can happen, allowing us to compute internal energy, heat, and work done for a thermodynamic system experiencing change sometimes during process.

A gas works as it spreads, and as a result, its internal energy reduces. W is therefore positive when the system performs work and negatives when the system is operating work. The summary of this sign convention is in.

Fundamental Thermodynamic Law

Each equilibrium point of a system has an internal energy $E_{int}$ connected with it. Any movement among any two thermodynamic equilibrium results in a change in $E_{int}$, where $E_{int} =Q-W$

$Q=U+W$

$200 = -100 + W$

$W = 300 joule$

Thus, the system has generated 300 joule of work.

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